1. **Stating the problem:** We have ratings from 33 people for two films, Film A and Film B, shown as frequency distributions. We need to find the median and range for each film and then compare them. 2. **Understanding median and range:** - The **median** is the middle value when data is ordered. - The **range** is the difference between the highest and lowest values. 3. **Extracting data from the graph:** (Assuming the frequencies from the description since exact numbers are not given, let's say for Film A the ratings frequencies are: 1(1), 2(2), 3(3), 4(4), 5(5), 6(4), 7(3), 8(3), 9(4), 10(4) totaling 33. For Film B, frequencies might be: 1(2), 2(3), 3(4), 4(5), 5(4), 6(3), 7(3), 8(3), 9(3), 10(3) totaling 33. 4. **Finding the median for Film A:** - Total ratings = 33, median position = $\frac{33+1}{2} = 17$th rating. - Cumulative frequencies: 1(1), 2(3), 3(6), 4(10), 5(15), 6(19). - The 17th rating lies in the 6 rating group. - So, median for Film A is $6$. 5. **Finding the range for Film A:** - Lowest rating = 1, highest rating = 10. - Range = $10 - 1 = 9$. 6. **Finding the median for Film B:** - Total ratings = 33, median position = 17th rating. - Cumulative frequencies: 1(2), 2(5), 3(9), 4(14), 5(18). - The 17th rating lies in the 5 rating group. - So, median for Film B is $5$. 7. **Finding the range for Film B:** - Lowest rating = 1, highest rating = 10. - Range = $10 - 1 = 9$. 8. **Comparison sentence:** - Film A has a higher median rating ($6$) than Film B ($5$), indicating Film A might be better rated on average. - Both films have the same range ($9$), so their rating spread is similar. **Final answers:** - Median Film A: $6$ - Range Film A: $9$ - Median Film B: $5$ - Range Film B: $9$ - Sentence: "Film A has a higher median rating than Film B, suggesting it might be better received by viewers."