1. **Problem Statement:** Find the probability that a student obtained a grade between the mean (86.08) and 91 in a General Mathematics exam where grades are normally distributed with mean $\mu = 86.08$ and standard deviation $\sigma = 6.44$. 2. **Formula Used:** The Z-score formula is: $$Z = \frac{X - \mu}{\sigma}$$ This converts a raw score $X$ to a standard normal variable $Z$. 3. **Convert X to Z-score:** Calculate the Z-score for $X = 91$: $$Z = \frac{91 - 86.08}{6.44} = \frac{4.92}{6.44} \approx 0.76$$ The mean corresponds to $Z = 0$. 4. **Find the Probability:** We want the probability $P(0 < Z < 0.76)$. From the Z-table: $$P(Z < 0.76) = 0.7764$$ $$P(Z < 0) = 0.5000$$ 5. **Calculate the Area Between Z-scores:** $$P(0 < Z < 0.76) = P(Z < 0.76) - P(Z < 0) = 0.7764 - 0.5000 = 0.2764$$ 6. **Conclusion:** There is approximately a 27.64% probability that a randomly selected student scored between the mean (86.08) and 91.