1. The problem is to find the probability that a standard normal variable $Z$ is greater than 1.46, i.e., $P(Z > 1.46)$. 2. We use the standard normal distribution table or a calculator to find $P(Z \leq 1.46)$, the cumulative probability up to 1.46. 3. The formula for the complement rule is: $$P(Z > 1.46) = 1 - P(Z \leq 1.46)$$ 4. From the standard normal table, $P(Z \leq 1.46) \approx 0.9279$. 5. Therefore, $$P(Z > 1.46) = 1 - 0.9279 = 0.0721$$ 6. This means there is approximately a 7.21% chance that $Z$ is greater than 1.46.