1. **State the problem:** We are given frequencies of responses about seat belt usage and need to find the probabilities for each response category by dividing each frequency by the total number of responses. 2. **Calculate total frequency:** $$146 + 312 + 576 + 1369 + 2499 = 4902$$ 3. **Calculate probabilities:** - Never: $$\frac{146}{4902} \approx 0.030$$ - Rarely: $$\frac{312}{4902} \approx 0.064$$ - Sometimes: $$\frac{576}{4902} \approx 0.118$$ - Most of the time: $$\frac{1369}{4902} \approx 0.279$$ - Always: $$\frac{2499}{4902} \approx 0.510$$ 4. **Answer part (b):** An event is considered unusual if its probability is less than 0.05. Since $$P(\text{Never}) = 0.030 < 0.05$$, it is unusual. Therefore, the correct choice is: **B. Yes, because P(never) < 0.05.**