1. The problem asks to find the relative frequency for the class with lower class limit 19, which corresponds to the age group 19-22. 2. Relative frequency is calculated by dividing the frequency of the class by the total number of observations, then multiplying by 100 to get a percentage. 3. From the table, the frequency for the class 19-22 is 4. 4. Calculate the total number of students by summing all frequencies: $$5 + 4 + 3 + 6 + 10 + 2 = 30$$ 5. Use the formula for relative frequency: $$\text{Relative Frequency} = \frac{\text{Frequency of class}}{\text{Total frequency}} \times 100$$ 6. Substitute the values: $$\text{Relative Frequency} = \frac{4}{30} \times 100$$ 7. Simplify the fraction: $$\frac{4}{30} = \frac{\cancel{2} \times 2}{\cancel{2} \times 15} = \frac{2}{15}$$ 8. Calculate the percentage: $$\frac{2}{15} \times 100 = \frac{200}{15} \approx 13.3333...$$ 9. Round to one decimal place: $$13.3\%$$ Final answer: The relative frequency for the class 19-22 is **13.3%**.