Subjects statistics

Relative Frequency F9Ed19

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1. **State the problem:** We are given per capita disposable income data for 25 cities and asked in part (b) to construct a relative frequency histogram with a first class lower limit of 30,000 and class width of 6000. 2. **Define class intervals:** Starting at 30,000 with width 6000, the classes are: - [30,000, 36,000) - [36,000, 42,000) - [42,000, 48,000) - [48,000, 54,000) 3. **Count data points in each class:** - [30,000, 36,000): Includes 30,127, 30,452, 30,710, 32,153, 32,969, 33,654, 33,859, 34,300, 34,643, 34,930, 35,181, 35,608, 35,833, 35,910 (14 values) - [36,000, 42,000): Includes 36,880, 37,248, 37,825, 38,450, 38,750, 38,924, 39,882, 40,274, 41,066, 41,401 (10 values) - [42,000, 48,000): No values fall in this range (0 values) - [48,000, 54,000): Includes 52,499 (1 value) 4. **Calculate relative frequencies:** - Total data points = 25 - Relative frequency = (class frequency) / 25 - [30,000, 36,000): 14/25 = 0.56 - [36,000, 42,000): 10/25 = 0.4 - [42,000, 48,000): 0/25 = 0 - [48,000, 54,000): 1/25 = 0.04 5. **Compare with given graphs:** - Graph A bars: 0.05, 0.4, 0.5, 0.1 (does not match our frequencies) - Graph B bars: 0.5, 0.4, very small, 0.05 (class intervals differ, so not correct) - Graph C bars: 0.5, 0.4, very small, 0.05 with intervals [30,36), [36,42), [42,48), [48,54) matches intervals and relative frequencies closely (0.56 ~ 0.5, 0.4, 0, 0.04 ~ 0.05) **Final answer:** The correct graph is **Graph C**.