1. Stating the problem. Problem: There are 61 responses distributed as 31% always, 31% sometimes, 20% often, and 18% never. 2. Formula and rules. To convert a percentage to a count use $\text{count}=\dfrac{\text{percentage}\times\text{total}}{100}$. Important rules: counts must be whole numbers so round to the nearest integer after computing each percentage. 3. Calculations. Always: $31\%$ of 61 is $0.31\times61=18.91$. Using fractions: $$\frac{31}{100}\times61=\frac{31\times61}{100}=\frac{1891}{100}=18.91$$ Sometimes: $31\%$ of 61 is the same as always and equals 18.91. Using fractions: $$\frac{31}{100}\times61=\frac{1891}{100}=18.91$$ Often: $20\%$ of 61 is $0.20\times61=12.2$. Using fractions and simplifying: $$\frac{20}{100}\times61=\frac{\cancel{20}}{\cancel{100}}\times61=\frac{1}{5}\times61=12.2$$ Never: $18\%$ of 61 is $0.18\times61=10.98$. Using fractions and simplifying: $$\frac{18}{100}\times61=\frac{\cancel{18}}{\cancel{100}}\times61=\frac{9}{50}\times61=10.98$$ 4. Rounding to whole responses. Round 18.91 to 19, 18.91 to 19, 12.2 to 12, and 10.98 to 11. So the counts are: Always 19, Sometimes 19, Often 12, Never 11. 5. Check sum. $$19+19+12+11=61$$ Final answer: Always 19, Sometimes 19, Often 12, Never 11.