Subjects statistics

Sample Standard Deviation 8787E7

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1. **State the problem:** We are given a sample of false fire alarm counts: 8, 6, 15, 6, and an unknown value. We need to compute the sample standard deviation using the given table and information. 2. **Identify the mean (\(\bar{x}\)) and missing values:** The table shows squared deviations from the mean, but the mean is unknown. The squared deviations given are 0, 4, (missing), 4, and 9. 3. **Use the squared deviations to find the mean:** The squared deviation for the first value is \((8 - \bar{x})^2 = 0\), which implies \(8 - \bar{x} = 0\) so \(\bar{x} = 8\). 4. **Check other squared deviations with \(\bar{x} = 8\):** - For \(x_2 = 6\), \((6 - 8)^2 = (-2)^2 = 4\) matches the table. - For \(x_4 = 6\), same calculation, 4. - For \(x_5\), squared deviation is 9, so \((x_5 - 8)^2 = 9\) which means \(x_5 - 8 = \pm 3\), so \(x_5 = 11\) or \(5\). 5. **Find the missing \(x_3\) and its squared deviation:** We know \(x_3 = 15\) from the problem statement. Calculate \((15 - 8)^2 = 7^2 = 49\). 6. **Calculate the average (mean) of the sample:** $$\bar{x} = \frac{8 + 6 + 15 + 6 + 11}{5} = \frac{46}{5} = 9.2$$ 7. **Calculate each squared deviation from the mean 9.2:** - \((8 - 9.2)^2 = (-1.2)^2 = 1.44\) - \((6 - 9.2)^2 = (-3.2)^2 = 10.24\) - \((15 - 9.2)^2 = 5.8^2 = 33.64\) - \((6 - 9.2)^2 = 10.24\) - \((11 - 9.2)^2 = 1.8^2 = 3.24\) 8. **Sum of squared deviations:** $$1.44 + 10.24 + 33.64 + 10.24 + 3.24 = 58.8$$ 9. **Calculate variance:** Sample variance formula is $$s^2 = \frac{\sum (x_i - \bar{x})^2}{n - 1} = \frac{58.8}{5 - 1} = \frac{58.8}{4} = 14.7$$ 10. **Calculate sample standard deviation:** $$s = \sqrt{14.7} \approx 3.83$$ **Final answer:** The sample standard deviation is approximately **3.83**.