1. **State the problem:** We are given a sample of false fire alarm counts: 8, 6, 15, 6, and an unknown value. We need to compute the sample standard deviation using the given table and information.
2. **Identify the mean (\(\bar{x}\)) and missing values:** The table shows squared deviations from the mean, but the mean is unknown. The squared deviations given are 0, 4, (missing), 4, and 9.
3. **Use the squared deviations to find the mean:** The squared deviation for the first value is \((8 - \bar{x})^2 = 0\), which implies \(8 - \bar{x} = 0\) so \(\bar{x} = 8\).
4. **Check other squared deviations with \(\bar{x} = 8\):**
- For \(x_2 = 6\), \((6 - 8)^2 = (-2)^2 = 4\) matches the table.
- For \(x_4 = 6\), same calculation, 4.
- For \(x_5\), squared deviation is 9, so \((x_5 - 8)^2 = 9\) which means \(x_5 - 8 = \pm 3\), so \(x_5 = 11\) or \(5\).
5. **Find the missing \(x_3\) and its squared deviation:**
We know \(x_3 = 15\) from the problem statement.
Calculate \((15 - 8)^2 = 7^2 = 49\).
6. **Calculate the average (mean) of the sample:**
$$\bar{x} = \frac{8 + 6 + 15 + 6 + 11}{5} = \frac{46}{5} = 9.2$$
7. **Calculate each squared deviation from the mean 9.2:**
- \((8 - 9.2)^2 = (-1.2)^2 = 1.44\)
- \((6 - 9.2)^2 = (-3.2)^2 = 10.24\)
- \((15 - 9.2)^2 = 5.8^2 = 33.64\)
- \((6 - 9.2)^2 = 10.24\)
- \((11 - 9.2)^2 = 1.8^2 = 3.24\)
8. **Sum of squared deviations:**
$$1.44 + 10.24 + 33.64 + 10.24 + 3.24 = 58.8$$
9. **Calculate variance:**
Sample variance formula is
$$s^2 = \frac{\sum (x_i - \bar{x})^2}{n - 1} = \frac{58.8}{5 - 1} = \frac{58.8}{4} = 14.7$$
10. **Calculate sample standard deviation:**
$$s = \sqrt{14.7} \approx 3.83$$
**Final answer:** The sample standard deviation is approximately **3.83**.
Sample Standard Deviation 8787E7
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