1. The problem asks how the slope $u$ of the new line of best fit compares to the original slope $t$ after removing point A. 2. The original line of best fit has slope $t$ and includes point A at approximately $(7,3)$, which lies below the original line. 3. Since point A is below the line, it pulls the original line downward near $x=7$, reducing the slope. 4. Removing point A means the new line of best fit is calculated without this low outlier. 5. Without point A, the line will fit the remaining points better, which are generally higher near $x=7$, so the slope $u$ will increase. 6. Therefore, the new slope $u$ is greater than the original slope $t$. Final answer: $u > t$ (Option B).