1. **State the problem:** We want to find how many students out of 1,500 spent more than 8 hours on social media, assuming the time spent follows a standard normal distribution. 2. **Identify the distribution and parameters:** The problem implies using the standard normal distribution $Z \sim N(0,1)$, but we need the mean and standard deviation of hours spent to convert 8 hours into a $Z$-score. Since these are not given, we assume the problem expects using the standard normal table for a given $Z$-score. 3. **Calculate the $Z$-score:** Suppose the mean time spent is $\mu$ and standard deviation is $\sigma$. The $Z$-score for 8 hours is: $$Z = \frac{8 - \mu}{\sigma}$$ 4. **Find the probability:** Using the standard normal table, find $P(Z > z)$, the probability that a student spends more than 8 hours. 5. **Calculate the number of students:** Multiply the probability by 1,500: $$\text{Number} = 1500 \times P(Z > z)$$ Since the problem does not provide $\mu$ or $\sigma$, we cannot compute the exact number without these values. If you provide mean and standard deviation, I can calculate the exact number. **Summary:** To solve this problem, you need the mean and standard deviation of hours spent on social media. Then calculate the $Z$-score for 8 hours, find the corresponding probability from the standard normal table, and multiply by 1,500 to get the number of students.