1. **State the problem:** We need to find how many students obtained marks greater than the average marks of the class based on the given histogram data. 2. **Data from histogram:** - Marks intervals and number of students: - 125-130: 1 student - 130-135: 3 students - 135-140: 2 students - 140-145: 8 students - 145-150: 5 students - 150-160: 4 + 1 = 5 students 3. **Calculate the midpoint of each interval (to approximate marks):** - 125-130 midpoint = $\frac{125 + 130}{2} = 127.5$ - 130-135 midpoint = $\frac{130 + 135}{2} = 132.5$ - 135-140 midpoint = $\frac{135 + 140}{2} = 137.5$ - 140-145 midpoint = $\frac{140 + 145}{2} = 142.5$ - 145-150 midpoint = $\frac{145 + 150}{2} = 147.5$ - 150-160 midpoint = $\frac{150 + 160}{2} = 155$ 4. **Calculate total number of students:** $$1 + 3 + 2 + 8 + 5 + 5 = 24$$ 5. **Calculate total marks (sum of midpoint × number of students):** $$\begin{aligned} &127.5 \times 1 + 132.5 \times 3 + 137.5 \times 2 + 142.5 \times 8 + 147.5 \times 5 + 155 \times 5 \\ &= 127.5 + 397.5 + 275 + 1140 + 737.5 + 775 \\ &= 3452.5 \end{aligned}$$ 6. **Calculate average marks:** $$\text{Average} = \frac{3452.5}{24} = 143.854\approx 143.85$$ 7. **Find number of students with marks greater than average (i.e., marks > 143.85):** - Intervals with midpoints greater than 143.85 are 145-150 and 150-160. - Number of students in these intervals: $5 + 5 = 10$ **Final answer:** 10 students obtained marks more than the average.