1. **State the problem:** Given a z-score $Z = 0.88$, find the corresponding area $A$ to the left of this z-score using the z-table.
2. **Formula and explanation:** The z-table gives the cumulative probability (area) from the far left of the normal distribution up to the given z-score.
3. **Look up the z-score:** Find $0.8$ row and $0.08$ column in the z-table.
4. **Intermediate step:** The value found in the z-table for $Z=0.88$ is approximately $0.8106$.
5. **Interpretation:** This means the area $A$ to the left of $Z=0.88$ is $0.8106$.
**Final answer:**
$$A = 0.8106$$
Z Score Area B83A30
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