1. The problem is to convert given z-scores to their corresponding x-values in a normal distribution. 2. The formula to convert a z-score to an x-value is: $$x = \mu + z \sigma$$ where $\mu$ is the mean and $\sigma$ is the standard deviation of the distribution. 3. Since the mean and standard deviation are not provided, we assume a standard normal distribution where $\mu = 0$ and $\sigma = 1$. 4. For $z = 0.2995$: $$x = 0 + 0.2995 \times 1 = 0.2995$$ 5. For $z = 0.4967$: $$x = 0 + 0.4967 \times 1 = 0.4967$$ 6. Therefore, the x-values corresponding to the z-scores are $0.2995$ and $0.4967$ respectively.