1. **Stating the problem:** Calculate the forces $F_q$ and $F_{q2}$ from the distributed load $q_n = 6$ kN/m acting on the beam. 2. **Formulas used:** - The force from a distributed load over a distance $d$ is given by: $$F_q = q_n \cdot d$$ - Similarly, for a distance $x$, the force is: $$F_{q2} = q_n \cdot x$$ 3. **Given values:** - $q_n = 6$ kN/m - Distances $d$ and $x$ are variables representing lengths over which the load acts. 4. **Calculations:** - For $F_q$: $$F_q = 6 \cdot d = 6d$$ - For $F_{q2}$: $$F_{q2} = 6 \cdot x = 6x$$ 5. **Explanation:** The distributed load $q_n$ applies a force proportional to the length over which it acts. Multiplying the load intensity by the length gives the total force exerted by the load on that segment of the beam. **Final answers:** $$F_q = 6d$$ $$F_{q2} = 6x$$