1. **Problem Statement:**
Calculate the volume (متره) and estimate the cost (براورد) of a floor slab made of تیرچه و یونولیت (joist and polystyrene) with a thickness of 30 cm, excluding the cost of steel reinforcement (میلگرد).
The floor plan consists of a grid with beams spaced 440 cm and 600 cm horizontally, and 400 cm and 340 cm vertically. Beam width is 40 cm.
2. **Step 1: Calculate the total floor area.**
The floor is divided into two rows and three columns of rectangular sections.
Horizontal lengths: $440 + 600 = 1040$ cm
Vertical lengths: $400 + 340 = 740$ cm
Convert to meters:
$$
\text{Length} = \frac{1040}{100} = 10.4\,m
$$
$$
\text{Width} = \frac{740}{100} = 7.4\,m
$$
Total floor area:
$$
A = 10.4 \times 7.4 = 76.96\,m^2
$$
3. **Step 2: Calculate the volume of the slab.**
Thickness is 30 cm = 0.3 m.
Volume:
$$
V = A \times \text{thickness} = 76.96 \times 0.3 = 23.088\,m^3
$$
4. **Step 3: Calculate the volume of beams.**
Beams run along the grid lines. There are 3 vertical beams and 3 horizontal beams.
Vertical beams length:
$$
3 \times 7.4 = 22.2\,m
$$
Horizontal beams length:
$$
3 \times 10.4 = 31.2\,m
$$
Total beam length:
$$
L = 22.2 + 31.2 = 53.4\,m
$$
Beam cross-section area:
$$
0.4\,m \times 0.3\,m = 0.12\,m^2
$$
Beam volume:
$$
V_b = L \times 0.12 = 53.4 \times 0.12 = 6.408\,m^3
$$
5. **Step 4: Calculate the volume of the joist and polystyrene slab excluding beams.**
Slab volume excluding beams:
$$
V_s = V - V_b = 23.088 - 6.408 = 16.68\,m^3
$$
6. **Step 5: Summary**
- Total slab volume (including beams): $23.088\,m^3$
- Beam volume: $6.408\,m^3$
- Joist and polystyrene volume: $16.68\,m^3$
7. **Step 6: Cost estimation**
To estimate cost, multiply volumes by unit prices of materials (not provided).
---
**Final answer:**
Total volume of slab including beams is **23.088 cubic meters**.
Beam volume is **6.408 cubic meters**.
Joist and polystyrene volume is **16.68 cubic meters**.
These volumes can be used for material quantity estimation and cost calculation excluding steel reinforcement.
Floor Volume 5Bc5Fa
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