1. **State the problem:** We have a right triangle formed by the flat ground, the vertical height of the airplane, and the slant distance from point T to the airplane P. We need to find the angle $E$ at point $T$. 2. **Identify the known values:** - Hypotenuse (distance from $T$ to $P$): $7.5$ km = $7500$ m (converted to meters for consistency) - Opposite side (height of airplane above ground): $200$ m 3. **Formula used:** To find angle $E$, we use the sine function in trigonometry: $$\sin(E) = \frac{\text{opposite}}{\text{hypotenuse}}$$ 4. **Calculate sine of angle $E$:** $$\sin(E) = \frac{200}{7500}$$ 5. **Simplify the fraction:** $$\sin(E) = \frac{\cancel{200}}{\cancel{7500}} = \frac{2}{75}$$ 6. **Find angle $E$ by taking the inverse sine:** $$E = \sin^{-1}\left(\frac{2}{75}\right)$$ 7. **Evaluate the inverse sine:** $$E \approx \sin^{-1}(0.0267) \approx 1.5^\circ$$ **Final answer:** The angle $E$ is approximately $1.5^\circ$ to one decimal place.