1. **State the problem:** We need to find the angle $\theta$ at Harpton between the north direction and the line connecting Harpton to Faywyn. 2. **Identify the given information:** Faywyn is 17 km east and 22 km north of Harpton. 3. **Visualize the problem:** This forms a right triangle where the horizontal leg (east) is 17 km and the vertical leg (north) is 22 km. 4. **Formula used:** The angle $\theta$ between the north direction and the line to Faywyn can be found using the tangent function: $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{17}{22}$$ 5. **Calculate $\theta$:** $$\theta = \tan^{-1}\left(\frac{17}{22}\right)$$ 6. **Evaluate the inverse tangent:** $$\theta = \tan^{-1}(0.7727)$$ 7. Using a calculator, $$\theta \approx 37.87^\circ$$ 8. **Round to the nearest degree:** $$\theta \approx 38^\circ$$ **Final answer:** The angle $\theta$ is approximately **38 degrees**.