1. **State the problem:** We need to find the angle $\theta$ in a right triangle where the legs adjacent to $\theta$ are both 3 units long.
2. **Identify the sides relative to $\theta$:** The side opposite $\theta$ is CA = 3, and the side adjacent to $\theta$ is BC = 3.
3. **Choose the trigonometric ratio:** Since we know the opposite and adjacent sides, we use the tangent ratio:
$$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{3}{3}$$
4. **Simplify the ratio:**
$$\tan(\theta) = \frac{\cancel{3}}{\cancel{3}} = 1$$
5. **Find $\theta$ using the inverse tangent function:**
$$\theta = \tan^{-1}(1)$$
6. **Calculate the angle:**
$$\theta = 45^\circ$$
7. **Round the answer:** The angle $\theta$ is already a whole number, so $\theta = 45^\circ$.
**Final answer:** $\theta = 45^\circ$
**Trig Ratio Used:** Tangent (tan)
Angle Theta B804D7
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