1. **State the problem:** Myesha stands 13 meters from a building. The angle of elevation to the roof (point A) is 29°, and to the top of the antenna (point B) is 43°. Her eye height is 1.51 meters. We need to find the height of the antenna (distance from A to B). 2. **Identify the known values:** - Horizontal distance $d = 13$ m - Angle to roof $\theta_A = 29^\circ$ - Angle to antenna top $\theta_B = 43^\circ$ - Eye height $h_e = 1.51$ m 3. **Use the tangent function:** The tangent of an angle in a right triangle is the ratio of the opposite side (height above eye level) to the adjacent side (horizontal distance): $$\tan(\theta) = \frac{\text{height above eye}}{d}$$ 4. **Calculate height to roof above eye level:** $$h_A = d \times \tan(\theta_A) = 13 \times \tan(29^\circ)$$ Calculate $\tan(29^\circ)$: $$\tan(29^\circ) \approx 0.5543$$ So, $$h_A = 13 \times 0.5543 = 7.206$$ 5. **Calculate height to antenna top above eye level:** $$h_B = d \times \tan(\theta_B) = 13 \times \tan(43^\circ)$$ Calculate $\tan(43^\circ)$: $$\tan(43^\circ) \approx 0.9325$$ So, $$h_B = 13 \times 0.9325 = 12.1225$$ 6. **Find the height of the roof and antenna above ground:** Add eye height to each: $$H_A = h_e + h_A = 1.51 + 7.206 = 8.716$$ $$H_B = h_e + h_B = 1.51 + 12.1225 = 13.6325$$ 7. **Find the height of the antenna (distance from A to B):** $$\text{Height of antenna} = H_B - H_A = 13.6325 - 8.716 = 4.9165$$ 8. **Round to nearest meter:** $$\boxed{5 \text{ meters}}$$ The antenna is approximately 5 meters tall.