Subjects trigonometry

Building Height 078267

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1. **State the problem:** We need to find the height of a building given that from a point 12 feet away from its base, the angle of elevation to the top is 70°. 2. **Identify the right triangle and trigonometric function:** The distance from the point to the building is the adjacent side, the height of the building is the opposite side, and the angle of elevation is 70°. 3. **Use the tangent function:** Tangent relates opposite and adjacent sides in a right triangle: $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$ Here, $$\theta = 70^\circ$$, opposite = height $$h$$, adjacent = 12 feet. 4. **Set up the equation:** $$\tan(70^\circ) = \frac{h}{12}$$ 5. **Solve for height $$h$$:** $$h = 12 \times \tan(70^\circ)$$ 6. **Calculate $$\tan(70^\circ)$$:** Using a calculator, $$\tan(70^\circ) \approx 2.747$$ 7. **Find $$h$$:** $$h = 12 \times 2.747 = 32.964$$ 8. **Conclusion:** The height of the building is approximately 33 feet.