1. **State the problem:** We need to find the height of the cliff given a right triangle where the horizontal distance from the person to the cliff is 7 meters, the angle of elevation to the top of the cliff is 74°, and the device is held at 1.68 meters above the ground. 2. **Identify the known values:** - Horizontal distance (adjacent side) $= 7$ m - Angle of elevation $= 74^\circ$ - Height of device above ground $= 1.68$ m 3. **Formula used:** We use the tangent function which relates the opposite side (height above the device) to the adjacent side: $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$ 4. **Calculate the height above the device:** $$\text{opposite} = \tan(74^\circ) \times 7$$ 5. **Evaluate $\tan(74^\circ)$:** $$\tan(74^\circ) \approx 3.487$$ 6. **Calculate opposite side:** $$\text{opposite} = 3.487 \times 7 = 24.409$$ 7. **Calculate total height of the cliff:** Add the height of the device to the opposite side: $$\text{height} = 24.409 + 1.68 = 26.089$$ 8. **Round to one decimal place:** $$26.1$$ meters **Final answer:** The height of the cliff is **26.1 meters**.