1. **State the problem:** We need to find the distance from the seat to the ball on the ground given the angle of depression is 28° and the seat is 5 m above ground. 2. **Diagram and variables:** Let the distance from the seat to the ball be $d$ meters. The height of the seat above the ground is 5 m. The angle of depression is 28°. 3. **Formula and explanation:** The angle of depression from the seat to the ball is equal to the angle of elevation from the ball to the seat (alternate interior angles). We can model this as a right triangle where: - Opposite side = 5 m (height) - Adjacent side = $d$ (distance we want to find) - Angle = 28° Using the tangent function: $$\tan(28^\circ) = \frac{\text{opposite}}{\text{adjacent}} = \frac{5}{d}$$ 4. **Solve for $d$:** $$d = \frac{5}{\tan(28^\circ)}$$ 5. **Calculate the value:** Using a calculator: $$\tan(28^\circ) \approx 0.5317$$ So, $$d = \frac{5}{0.5317} \approx 9.4$$ 6. **Final answer:** The distance from the seat to the ball is approximately **9.4 meters**.