1. **State the problem:** From a seat 5 m above ground, the angle of depression to a ball on level ground is 28°. Find the distance from the seat to the ball. 2. **Understand the scenario:** The seat is 5 m above the ground, and the ball is on the ground. The angle of depression is the angle between the horizontal line from the seat and the line of sight to the ball. 3. **Set up the right triangle:** Let the horizontal distance from the seat to the ball be $x$ meters. The vertical height is 5 m. The angle of depression is 28°, so the angle between the vertical line and the line of sight is complementary to 28°, but we use the angle of depression directly with tangent. 4. **Use the tangent function:** $$\tan(28^\circ) = \frac{\text{opposite}}{\text{adjacent}} = \frac{5}{x}$$ 5. **Solve for $x$:** $$x = \frac{5}{\tan(28^\circ)}$$ 6. **Calculate $x$:** Using a calculator, $$\tan(28^\circ) \approx 0.5317$$ $$x = \frac{5}{0.5317} \approx 9.4$$ 7. **Find the distance from the seat to the ball:** The distance is the hypotenuse $d$ of the right triangle with sides 5 m and $x$ m. 8. **Use Pythagoras theorem:** $$d = \sqrt{5^2 + x^2} = \sqrt{25 + 9.4^2} = \sqrt{25 + 88.36} = \sqrt{113.36} \approx 10.64$$ **Final answer:** The distance from the seat to the ball is approximately **10.64 meters**.