1. **Problem statement:** Shawn measures the angle of elevation to the top of a 450 feet high tower as 32°.
We need to find the horizontal distance from Shawn to the base of the tower.
2. **Diagram and triangle setup:**
- Right triangle with:
- Opposite side (height of tower) = 450 feet
- Angle of elevation = 32°
- Adjacent side (distance from Shawn to tower base) = unknown, call it $x$
3. **Formula used:**
The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side:
$$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$
Here, $\theta = 32^\circ$, opposite = 450, adjacent = $x$.
4. **Set up the equation:**
$$\tan(32^\circ) = \frac{450}{x}$$
5. **Solve for $x$:**
$$x = \frac{450}{\tan(32^\circ)}$$
6. **Calculate $\tan(32^\circ)$:**
Using a calculator, $\tan(32^\circ) \approx 0.6249$
7. **Find $x$:**
$$x = \frac{450}{0.6249} \approx 720.1$$
8. **Answer:**
Shawn is approximately 720.1 feet away from the base of the tower.
This means the horizontal distance from Shawn to the tower base is about 720 feet.
Distance Tower Ca0109
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.