1. **State the problem:** Rakeem sees his drone at an angle of elevation of 29° from his eye level, which is 6 feet above the ground. The drone is 107 feet above the ground. We need to find the distance from Rakeem's eye to the drone (the hypotenuse of the right triangle). 2. **Identify the triangle sides:** - Vertical side from Rakeem's eye to the ground: 6 ft - Vertical height of drone from ground: 107 ft - Therefore, vertical side from Rakeem's eye to drone: $107 - 6 = 101$ ft - Angle of elevation at Rakeem's eye: $29^\circ$ - Hypotenuse (distance from eye to drone): unknown, call it $x$ 3. **Use trigonometric formula:** The sine of the angle relates the opposite side (vertical height difference) to the hypotenuse: $$\sin(29^\circ) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{101}{x}$$ 4. **Solve for $x$:** $$x = \frac{101}{\sin(29^\circ)}$$ 5. **Calculate $\sin(29^\circ)$:** $$\sin(29^\circ) \approx 0.4848$$ 6. **Substitute and simplify:** $$x = \frac{101}{0.4848}$$ 7. **Final calculation:** $$x \approx 208.3$$ **Answer:** The distance from Rakeem's eye to the drone is approximately **208.3 feet**.