1. **State the problem:** We need to find the height above the ground of the emergency exit, which is the side opposite the 15° angle in a right triangle where the hypotenuse is 35 feet. 2. **Formula used:** In a right triangle, the sine of an angle is the ratio of the length of the opposite side to the hypotenuse: $$\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$$ 3. **Apply the formula:** Here, $\theta = 15^\circ$, hypotenuse $= 35$ feet, and opposite side is the height $h$: $$\sin(15^\circ) = \frac{h}{35}$$ 4. **Solve for $h$:** $$h = 35 \times \sin(15^\circ)$$ 5. **Use the given value:** $\sin(15^\circ) = 0.259$ $$h = 35 \times 0.259 = 9.065$$ 6. **Round to nearest 0.1 foot:** $$h \approx 9.1$$ **Final answer:** The height above the ground is approximately **9.1 feet**.