1. The problem asks to find the angle from the equation previously solved. 2. To find an angle from an equation involving trigonometric functions, we typically use inverse trigonometric functions such as $\theta = \arcsin(x)$, $\theta = \arccos(x)$, or $\theta = \arctan(x)$ depending on the context. 3. Since the previous equation is not provided here, let's assume it was of the form $\sin \theta = a$, $\cos \theta = b$, or $\tan \theta = c$. 4. For example, if the equation was $\sin \theta = \frac{1}{2}$, then the angle $\theta$ is found by $\theta = \arcsin\left(\frac{1}{2}\right)$. 5. Evaluating this, $\theta = 30^\circ$ or $\theta = \frac{\pi}{6}$ radians. 6. Remember that trigonometric functions are periodic, so there may be multiple solutions depending on the domain. 7. If you provide the exact equation, I can give the precise angle.