1. **State the problem:** We have a right triangle with a base of length 485, angles 28.7° and 40.3°, and we need to find the height $h$ opposite the 40.3° angle.
2. **Identify the relevant formula:** In a right triangle, the height opposite an angle can be found using the sine function:
$$\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$$
Here, $h$ is opposite the 40.3° angle, and the hypotenuse is unknown.
3. **Find the hypotenuse:** The base is adjacent to the 28.7° angle, so
$$\cos(28.7^\circ) = \frac{485}{\text{hypotenuse}}$$
Rearranged:
$$\text{hypotenuse} = \frac{485}{\cos(28.7^\circ)}$$
4. **Calculate the hypotenuse:**
$$\text{hypotenuse} = \frac{485}{\cos(28.7^\circ)}$$
5. **Find $h$ using sine:**
$$h = \sin(40.3^\circ) \times \text{hypotenuse} = \sin(40.3^\circ) \times \frac{485}{\cos(28.7^\circ)}$$
6. **Simplify and calculate:**
$$h = 485 \times \frac{\sin(40.3^\circ)}{\cos(28.7^\circ)}$$
7. **Evaluate the trigonometric values:**
$$\sin(40.3^\circ) \approx 0.647$$
$$\cos(28.7^\circ) \approx 0.877$$
8. **Calculate $h$ numerically:**
$$h \approx 485 \times \frac{0.647}{0.877} = 485 \times 0.738 = 357.93$$
9. **Round to the nearest integer:**
$$h \approx 358$$
**Final answer:**
$$\boxed{358}$$
Find Height Ef5115
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.