1. **State the problem:** We have a flagpole supported by four metal braces. Each brace makes an angle of 55° with the ground and meets the pole 6.2 m above the ground. We need to find the total length of all four metal braces.
2. **Identify the known values:**
- Height where braces meet the pole: $h = 6.2$ m
- Angle between each brace and the ground: $\theta = 55^\circ$
- Number of braces: 4
3. **Formula used:** The braces form the hypotenuse of a right triangle where the height is the opposite side to the angle $\theta$. Using the sine function:
$$\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{h}{L}$$
where $L$ is the length of one brace.
4. **Solve for $L$:**
$$L = \frac{h}{\sin(\theta)}$$
5. **Calculate $L$:**
$$L = \frac{6.2}{\sin(55^\circ)}$$
Calculate $\sin(55^\circ)$:
$$\sin(55^\circ) \approx 0.8192$$
So,
$$L = \frac{6.2}{0.8192} \approx 7.57 \text{ m}$$
6. **Find total length of all four braces:**
$$\text{Total length} = 4 \times L = 4 \times 7.57 = 30.28 \text{ m}$$
**Final answer:** The total length of the four metal braces is approximately **30.28 m**.
Flagpole Braces Caeb1B
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