1. **Problem statement:** A 2 m tall boy is flying a kite. The kite string length is 300 m and it makes an angle of 45 degrees with the horizon. We need to find the height of the kite above the ground. 2. **Formula used:** To find the height of the kite above the boy's hand, we use the trigonometric relation for the vertical component of the string: $$\text{height above boy's hand} = \text{string length} \times \sin(\theta)$$ where $\theta = 45^\circ$. 3. **Calculate height above boy's hand:** $$= 300 \times \sin(45^\circ)$$ Since $\sin(45^\circ) = \frac{\sqrt{2}}{2}$, $$= 300 \times \frac{\sqrt{2}}{2} = 150\sqrt{2}$$ 4. **Calculate total height above ground:** The boy is 2 m tall, so total height is: $$= 2 + 150\sqrt{2}$$ 5. **Approximate numerical value:** Since $\sqrt{2} \approx 1.414$, $$= 2 + 150 \times 1.414 = 2 + 212.1 = 214.1$$ **Final answer:** The kite is approximately 214.1 meters above the ground.