1. **Problem statement:**
We have a ladder leaning against a wall forming a right triangle. The foot of the ladder is 2 m from the wall, and the angle between the ladder and the ground is 68°.
2. **What is asked?**
(a) Find the height the ladder reaches on the wall.
(b) Find the length of the ladder.
3. **Relevant formulas and rules:**
- Use trigonometric ratios in a right triangle.
- The angle given is between the ladder (hypotenuse) and the ground (adjacent side).
- Height corresponds to the side opposite the angle.
- Ladder length is the hypotenuse.
4. **Step (a): Find the height (opposite side):**
Use the tangent function:
$$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$
Here, $\theta = 68^\circ$, adjacent = 2 m.
Calculate height:
$$\text{height} = 2 \times \tan(68^\circ)$$
Using a calculator:
$$\tan(68^\circ) \approx 2.4751$$
So,
$$\text{height} = 2 \times 2.4751 = 4.9502 \text{ m}$$
5. **Step (b): Find the ladder length (hypotenuse):**
Use the cosine function:
$$\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}$$
Rearranged:
$$\text{hypotenuse} = \frac{\text{adjacent}}{\cos(\theta)} = \frac{2}{\cos(68^\circ)}$$
Calculate:
$$\cos(68^\circ) \approx 0.3746$$
So,
$$\text{hypotenuse} = \frac{2}{0.3746} = 5.34 \text{ m}$$
**Final answers:**
(a) The ladder reaches approximately $4.95$ m up the wall.
(b) The ladder length is approximately $5.34$ m.
Ladder Triangle D4E3E7
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