1. **Problem statement:** Find the missing side $x$ in the triangle with given side 14 m opposite angle 65°, and angle opposite $x$ is 44°. 2. **Formula used:** Law of Sines states that for any triangle, $$\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}$$ where $a,b,c$ are sides opposite angles $A,B,C$ respectively. 3. **Apply Law of Sines:** $$\frac{x}{\sin 44^\circ} = \frac{14}{\sin 65^\circ}$$ 4. **Solve for $x$:** $$x = 14 \times \frac{\sin 44^\circ}{\sin 65^\circ}$$ 5. **Calculate sine values:** $$\sin 44^\circ \approx 0.6947, \quad \sin 65^\circ \approx 0.9063$$ 6. **Substitute values:** $$x = 14 \times \frac{0.6947}{0.9063}$$ 7. **Simplify fraction:** $$x = 14 \times \cancel{\frac{0.6947}{0.9063}}$$ 8. **Calculate fraction:** $$\frac{0.6947}{0.9063} \approx 0.7665$$ 9. **Final calculation:** $$x = 14 \times 0.7665 = 10.73$$ **Answer:** The missing side $x$ is approximately **10.73 meters**.