1. **State the problem:** We have two poles. Pole 1 is 6 feet tall. The distance between the poles is 8 feet, and the line from the top of pole 1 to the top of pole 2 is at a 15 degree downward angle. We need to find the height of pole 2. 2. **Identify the formula and concepts:** We can model this as a right triangle where the horizontal distance between poles is 8 feet, and the angle of depression from the top of pole 1 to the top of pole 2 is 15 degrees. 3. **Set up the relationship:** The vertical drop from pole 1's top to pole 2's top is given by the opposite side of the angle in the right triangle: $$\text{vertical drop} = 8 \times \tan(15^\circ)$$ 4. **Calculate the vertical drop:** $$\tan(15^\circ) \approx 0.2679$$ $$\text{vertical drop} = 8 \times 0.2679 = 2.1432$$ 5. **Find the height of pole 2:** Since pole 2 is lower by this vertical drop, $$\text{height of pole 2} = 6 - 2.1432 = 3.8568$$ 6. **Final answer:** The height of pole 2 is approximately **3.86 feet**.