1. **Problem statement:** A surveyor moves 140 feet away from the base of a pole and measures the angle of elevation to the top of the pole as 44° using a transit 4 feet tall. Find the height of the pole to the nearest foot. 2. **Formula and explanation:** We use the tangent function in a right triangle, where $ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} $. 3. **Define variables:** Let $ h $ be the height of the pole above the ground. The transit is 4 feet tall, so the total height is $ h + 4 $. 4. **Set up the equation:** $$ \tan(44^\circ) = \frac{h}{140} $$ 5. **Solve for $ h $:** $$ h = 140 \times \tan(44^\circ) $$ 6. **Calculate $ \tan(44^\circ) $:** Using a calculator, $ \tan(44^\circ) \approx 0.9657 $. 7. **Find $ h $:** $$ h = 140 \times 0.9657 = 135.198 $$ 8. **Add the transit height:** $$ \text{Total height} = h + 4 = 135.198 + 4 = 139.198 $$ 9. **Round to the nearest foot:** $$ \boxed{139} \text{ feet} $$ This is the height of the pole to the nearest foot.