1. **Problem statement:** Dylan is 12 m away from a rock, and the angle of elevation to the top of the rock is 57°. We need to find the height of the rock.
2. **Formula used:** To find the height of an object using the angle of elevation, we use the tangent function from trigonometry:
$$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{h}{d}$$
where $\theta$ is the angle of elevation, $h$ is the height of the rock, and $d$ is the distance from the observer to the rock.
3. **Apply the formula:**
$$\tan(57^\circ) = \frac{h}{12}$$
4. **Solve for $h$:**
$$h = 12 \times \tan(57^\circ)$$
5. **Calculate the value:**
Using a calculator,
$$\tan(57^\circ) \approx 1.5399$$
So,
$$h = 12 \times 1.5399 = 18.4788$$
6. **Final answer:**
The height of the rock is approximately **18.48 m**.
Rock Height Bec5F2
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