1. **State the problem:** Simplify the expression $2\sin^2 x + \sin x - \cos^2 x$.
2. **Recall the Pythagorean identity:** $\sin^2 x + \cos^2 x = 1$.
3. **Rewrite $\cos^2 x$ using the identity:**
$$\cos^2 x = 1 - \sin^2 x$$
4. **Substitute into the expression:**
$$2\sin^2 x + \sin x - (1 - \sin^2 x)$$
5. **Simplify inside the parentheses:**
$$2\sin^2 x + \sin x - 1 + \sin^2 x$$
6. **Combine like terms:**
$$2\sin^2 x + \sin^2 x + \sin x - 1 = 3\sin^2 x + \sin x - 1$$
7. **Final simplified expression:**
$$3\sin^2 x + \sin x - 1$$
This is the simplified form of the original expression.
Simplify Trig Expression 75456B
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