1. **Problem:** Find the exact value of $\sin(225^\circ)$.
2. **Formula and rules:** The sine of an angle in the unit circle can be found using reference angles and the signs in each quadrant. Since $225^\circ$ is in the third quadrant, where sine is negative, and its reference angle is $225^\circ - 180^\circ = 45^\circ$, we use:
$$\sin(225^\circ) = -\sin(45^\circ)$$
Recall that $\sin(45^\circ) = \frac{\sqrt{2}}{2}$.
3. **Calculation:**
$$\sin(225^\circ) = -\frac{\sqrt{2}}{2}$$
4. **Explanation:** The angle $225^\circ$ lies in the third quadrant where sine values are negative. The reference angle is $45^\circ$, so the sine value is the negative of $\sin(45^\circ)$.
**Final answer:**
$$\boxed{-\frac{\sqrt{2}}{2}}$$
Sin 225 20A929
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