1. The problem is to find the value of $\sin\frac{2\pi}{3}$.\n\n2. Recall that $\sin$ is a trigonometric function that gives the y-coordinate of a point on the unit circle corresponding to an angle.\n\n3. The angle $\frac{2\pi}{3}$ radians is in the second quadrant where sine values are positive.\n\n4. Use the reference angle: $\pi - \frac{2\pi}{3} = \frac{\pi}{3}$.\n\n5. Since $\sin(\pi - x) = \sin x$, we have $\sin\frac{2\pi}{3} = \sin\frac{\pi}{3}$.\n\n6. The value of $\sin\frac{\pi}{3}$ is $\frac{\sqrt{3}}{2}$.\n\n7. Therefore, $\sin\frac{2\pi}{3} = \frac{\sqrt{3}}{2}$.\n\nFinal answer: $$\sin\frac{2\pi}{3} = \frac{\sqrt{3}}{2}$$