1. **Problem statement:** Express $\sin 325^\circ$ in terms of $p$ given that $\sin 35^\circ = p$. 2. **Recall the sine function property:** $$\sin(360^\circ - \theta) = -\sin \theta$$ This means sine of an angle in the fourth quadrant is the negative sine of its reference angle. 3. **Apply the property:** Since $325^\circ = 360^\circ - 35^\circ$, we have $$\sin 325^\circ = \sin(360^\circ - 35^\circ) = -\sin 35^\circ$$ 4. **Substitute $\sin 35^\circ = p$:** $$\sin 325^\circ = -p$$ 5. **Final answer:** $\boxed{\sin 325^\circ = -p}$