1. **State the problem:** Find the value of $\sin(\arccos(\frac{15}{17}))$. 2. **Recall the relationship:** If $\theta = \arccos(x)$, then $\cos(\theta) = x$ and $\sin(\theta) = \sqrt{1 - \cos^2(\theta)}$ because $\sin^2(\theta) + \cos^2(\theta) = 1$. 3. **Apply the formula:** Here, $\cos(\theta) = \frac{15}{17}$. 4. **Calculate $\sin(\theta)$:** $$\sin(\theta) = \sqrt{1 - \left(\frac{15}{17}\right)^2} = \sqrt{1 - \frac{225}{289}} = \sqrt{\frac{289}{289} - \frac{225}{289}} = \sqrt{\frac{64}{289}}$$ 5. **Simplify the square root:** $$\sin(\theta) = \frac{8}{17}$$ 6. **Final answer:** $$\sin(\arccos(\frac{15}{17})) = \frac{8}{17}$$