1. **Problem statement:** Find the trigonometric values of $\sin \omega$ and $\cos \omega$ given the point $M(-0.8, 0.6)$ on the unit circle in the second quadrant, where $\omega = A\hat{O}M$ is the angle formed at the origin. 2. **Recall:** On the unit circle, the coordinates of a point $M(\cos \omega, \sin \omega)$ correspond to the cosine and sine of the angle $\omega$ respectively. 3. **Given:** The point $M$ has coordinates approximately $(-0.8, 0.6)$. 4. **Interpretation:** Since $M$ lies on the unit circle, $\cos \omega = -0.8$ and $\sin \omega = 0.6$. 5. **Verification:** Check that $\sin^2 \omega + \cos^2 \omega = 1$: $$(-0.8)^2 + (0.6)^2 = 0.64 + 0.36 = 1$$ This confirms the point lies on the unit circle. 6. **Answer:** $$\sin \omega = 0.6$$ $$\cos \omega = -0.8$$