1. **State the problem:** We are given a right triangle with vertices L, N, and M, where angle N is the right angle. The sides are LN = 5, NM = 12, and hypotenuse LM = 13. We need to find $\sin(L)$ rounded to two decimal places.
2. **Recall the formula:** For any angle in a right triangle, $\sin(\theta) = \frac{\text{opposite side}}{\text{hypotenuse}}$.
3. **Identify the opposite side to angle L:** The side opposite angle L is NM, which is 12.
4. **Calculate $\sin(L)$:**
$$\sin(L) = \frac{12}{13}$$
5. **Evaluate the fraction:**
$$\frac{12}{13} \approx 0.9230769$$
6. **Round to two decimal places:**
$$\sin(L) \approx 0.92$$
---
7. **Second question:** Write $\sin 30^\circ$ as a fraction.
8. **Recall the special right triangle rule:** $\sin 30^\circ = \frac{1}{2}$.
**Final answers:**
- $\sin(L) \approx 0.92$
- $\sin 30^\circ = \frac{1}{2}$
Sin L 30 1537B1
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.