1. The problem asks which triangle shows the equation $\sin \Theta = \frac{15}{17}$. 2. Recall the definition of sine in a right triangle: $$\sin \Theta = \frac{\text{opposite side}}{\text{hypotenuse}}$$ 3. We need to find the triangle where the ratio of the opposite side to the hypotenuse equals $\frac{15}{17}$. 4. Check each triangle's opposite side and hypotenuse: - Triangle A: opposite = 15 m, hypotenuse = 17 m, so $\sin \Theta = \frac{15}{17}$. - Triangle B: opposite = 15 m, hypotenuse = 17 m, so $\sin \Theta = \frac{15}{17}$. - Triangle C: opposite = 8 m, hypotenuse = 17 m, so $\sin \Theta = \frac{8}{17}$. - Triangle D: opposite = 8 m, hypotenuse = 17 m, so $\sin \Theta = \frac{8}{17}$. 5. Therefore, triangles A and B satisfy the equation $\sin \Theta = \frac{15}{17}$. 6. Since the question asks which triangle shows the equation, the answer is Triangle A and Triangle B. Final answer: Triangles A and B show $\sin \Theta = \frac{15}{17}$.