1. **State the problem:** Find the sine of angle $F$ in right triangle $EFD$ where $\angle D$ is the right angle, $EF=89$ (hypotenuse), $ED=80$, and $DF=39$. 2. **Recall the formula:** The sine of an angle in a right triangle is given by $$\sin(\theta) = \frac{\text{opposite side}}{\text{hypotenuse}}$$ 3. **Identify sides relative to angle $F$:** - Opposite side to $F$ is $ED = 80$ - Hypotenuse is $EF = 89$ 4. **Apply the formula:** $$\sin(F) = \frac{ED}{EF} = \frac{80}{89}$$ 5. **Simplify the fraction:** - $80$ and $89$ have no common factors other than 1, so the fraction is already in simplest form. 6. **Final answer:** $$\sin(F) = \frac{80}{89}$$ This is the exact value of $\sin(F)$ as a proper fraction.