1. The problem states that the curve is $y = \sin x^\circ$ and point A is where the curve returns to the x-axis after rising to a maximum height of 2 units. 2. Normally, the sine function $y = \sin x^\circ$ has a maximum value of 1, but here the maximum height is 2, so the curve is actually $y = 2\sin x^\circ$. 3. The sine function returns to zero at $x = 0^\circ, 180^\circ, 360^\circ, \ldots$. 4. Since point A is the first point after the origin where the curve returns to the x-axis, its x-coordinate is $180^\circ$ and y-coordinate is 0. 5. Therefore, the coordinates of point A are $(180, 0)$. Final answer: (a) Coordinates of point A: $(180, 0)$ (b) The graph of $y = \sin 2x^\circ$ oscillates twice as fast as $y = \sin x^\circ$, so it completes one full cycle in $180^\circ$ instead of $360^\circ$. This means the graph will have twice as many peaks and troughs in the same interval.