1. **State the problem:** We need to write the equation of a sine function in the form $$y = A \sin(Bx + C) + D$$ based on the given graph.
2. **Identify key features from the graph:**
- The wave oscillates between -4 and 4, so the amplitude $$A = 4$$.
- The midline (vertical shift) is at $$y = 0$$, so $$D = 0$$.
- The wave passes through the origin (0,0), which is a zero crossing point of the sine function.
- The period can be found by observing the distance between two consecutive peaks or troughs.
3. **Calculate the period:**
- Peaks occur near $$x = -\frac{3\pi}{2}$$ and $$x = \frac{\pi}{2}$$.
- The distance between these peaks is $$\frac{\pi}{2} - \left(-\frac{3\pi}{2}\right) = \frac{\pi}{2} + \frac{3\pi}{2} = 2\pi$$.
- So, the period $$T = 2\pi$$.
4. **Calculate $$B$$:**
- The formula for period is $$T = \frac{2\pi}{B}$$.
- Substitute $$T = 2\pi$$:
$$2\pi = \frac{2\pi}{B}$$
- Multiply both sides by $$B$$:
$$2\pi B = 2\pi$$
- Divide both sides by $$2\pi$$:
$$\cancel{2\pi} B = \cancel{2\pi}$$
$$B = 1$$
5. **Calculate phase shift $$C$$:**
- Since the sine wave passes through the origin (0,0) and matches the basic sine function shape, the phase shift $$C = 0$$.
6. **Write the final equation:**
$$y = 4 \sin(1 \cdot x + 0) + 0 = 4 \sin x$$
**Final answer:** $$\boxed{y = 4 \sin x}$$
Sine Function 272F2C
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