1. **State the problem:** We are given an angle $\theta$ with terminal point $\left(\frac{3}{6}, \frac{\sqrt{11}}{6}\right)$ on the unit circle. We need to find which value is equivalent to $\sin \theta$. 2. **Recall the definition of sine on the unit circle:** For an angle $\theta$ on the unit circle, the coordinates of the terminal point are $(\cos \theta, \sin \theta)$. 3. **Identify sine from the coordinates:** Since the terminal point is $\left(\frac{3}{6}, \frac{\sqrt{11}}{6}\right)$, the $x$-coordinate is $\frac{3}{6}$ and the $y$-coordinate is $\frac{\sqrt{11}}{6}$. 4. **Conclusion:** By definition, $\sin \theta$ is the $y$-coordinate of the terminal point on the unit circle. **Final answer:** $$\sin \theta = \frac{\sqrt{11}}{6}$$ Therefore, the value equivalent to $\sin \theta$ is the $y$-coordinate of the terminal point.