1. **State the problem:** We are given two sine wave functions: $$v_1 = A \sin(x\pi t + \frac{\pi}{6})$$ and $$v_2 = B \sin\left(\left(\frac{\pi}{3} + y\right)t\right)$$ with parameters for Student No. 16: $A=4.5$, $x=280$, $B=9$, $y=270$. 2. **Write the specific functions:** $$v_1 = 4.5 \sin(280\pi t + \frac{\pi}{6})$$ $$v_2 = 9 \sin\left(\left(\frac{\pi}{3} + 270\right)t\right)$$ 3. **Simplify the second function's argument:** Note that $y=270$ is in radians added to $\frac{\pi}{3}$: $$\frac{\pi}{3} + 270$$ Since $270$ is a large number, it remains as is in the argument. 4. **Interpretation:** - $v_1$ is a sine wave with amplitude 4.5, angular frequency $280\pi$, and phase shift $\frac{\pi}{6}$. - $v_2$ is a sine wave with amplitude 9, angular frequency $\frac{\pi}{3} + 270$, and zero phase shift. 5. **Final expressions:** $$v_1 = 4.5 \sin(280\pi t + \frac{\pi}{6})$$ $$v_2 = 9 \sin\left(\left(\frac{\pi}{3} + 270\right)t\right)$$ These are the explicit forms of the two voltage functions for Student No. 16. **Note:** To solve for specific values of $t$, substitute $t$ into these expressions.