1. The problem states: Given that $f(x) = 9$, find $f(x) = \sin x$. 2. This seems to be a misunderstanding because $f(x)$ cannot be both a constant 9 and $\sin x$ simultaneously. 3. If the problem is to find $x$ such that $\sin x = 9$, we note that the sine function only takes values between $-1$ and $1$. 4. Since 9 is outside the range of sine, there is no solution for $x$ where $\sin x = 9$. 5. Therefore, the equation $\sin x = 9$ has no real solutions. Final answer: No real solution exists for $\sin x = 9$ because $\sin x \in [-1,1]$ for all real $x$.