Subjects trigonometry

Skyscraper Height F367B8

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1. **State the problem:** Isaac's eye is 1.63 meters above the ground. He measures the angle of elevation to the top of a skyscraper as 17° while standing 294 meters away horizontally. We need to find the total height of the skyscraper. 2. **Identify the right triangle and variables:** - Horizontal distance (adjacent side) = 294 m - Angle of elevation = 17° - Vertical side = height of skyscraper - 1.63 m 3. **Use the tangent function:** The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side: $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$ 4. **Set up the equation:** $$\tan(17^\circ) = \frac{h - 1.63}{294}$$ where $h$ is the height of the skyscraper. 5. **Solve for $h$:** Multiply both sides by 294: $$294 \times \tan(17^\circ) = h - 1.63$$ 6. **Add 1.63 to both sides:** $$h = 294 \times \tan(17^\circ) + 1.63$$ 7. **Calculate the value:** First, calculate $\tan(17^\circ)$: $$\tan(17^\circ) \approx 0.3057$$ Then, $$h = 294 \times 0.3057 + 1.63 = 89.4778 + 1.63 = 91.1078$$ 8. **Round to the nearest hundredth:** $$h \approx 91.11 \text{ meters}$$ **Final answer:** The height of the skyscraper is approximately **91.11 meters**.